WEBAPI中的Request是HttpRequestMessage类型，不能像Web传统那样有querystring和from 方法接收参数，而传统的HttpReqest的基类是HttpReqestBase
所以这里我们就直接使用(HttpContextBase)Request.Properties[“MS_HttpContext”]
public void Post([FromBody]string value) { HttpContextBase context = (HttpContextBase)Request.Properties["MS_HttpContext"];//获取传统context HttpRequestBase request = context.Request;//定义传统request对象 string name = request.Form["name"]; }
1.获取遍历路由参数
//获取路由参数 IDictionary<string, object> dic = this.RequestContext.RouteData.Values; StringBuilder builder = new StringBuilder(); foreach (var item in dic) { builder.AppendFormat("key:{0},value:{1}", item.Key, item.Value); builder.AppendLine(); } return builder.ToString();
2.遍历表单参数
////获取表单参数 HttpContextBase context = (HttpContextBase)Request.Properties["MS_HttpContext"];//获取传统context HttpRequestBase request = context.Request;//定义传统request对象 StringBuilder builder = new StringBuilder(); foreach (string item in request.Form.Keys) { builder.AppendFormat("key:{0},value:{1}", item, request.Form[item]); builder.AppendLine(); } return builder.ToString();
版权声明：本文内容由互联网用户自发贡献，该文观点仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请联系我们举报，一经查实，本站将立刻删除。
发布者：全栈程序员-站长，转载请注明出处：https://javaforall.net/109190.html原文链接：https://javaforall.net
