POJ 3009-Curling 2.0(DFS)

POJ 3009-Curling 2.0(DFS)

大家好,又见面了,我是全栈君,今天给大家准备了Idea注册码。

Curling 2.0
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 12158   Accepted: 5125

Description

On Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from ours. The game is played on an ice game board on which a square mesh is marked. They use only a single stone. The purpose of the game is to lead the stone from the start to the goal with the minimum number of moves.

Fig. 1 shows an example of a game board. Some squares may be occupied with blocks. There are two special squares namely the start and the goal, which are not occupied with blocks. (These two squares are distinct.) Once the stone begins to move, it will proceed until it hits a block. In order to bring the stone to the goal, you may have to stop the stone by hitting it against a block, and throw again.

POJ 3009-Curling 2.0(DFS)
Fig. 1: Example of board (S: start, G: goal)

The movement of the stone obeys the following rules:

  • At the beginning, the stone stands still at the start square.
  • The movements of the stone are restricted to x and y directions. Diagonal moves are prohibited.
  • When the stone stands still, you can make it moving by throwing it. You may throw it to any direction unless it is blocked immediately(Fig. 2(a)).
  • Once thrown, the stone keeps moving to the same direction until one of the following occurs:
    • The stone hits a block (Fig. 2(b), (c)).
      • The stone stops at the square next to the block it hit.
      • The block disappears.
    • The stone gets out of the board.
      • The game ends in failure.
    • The stone reaches the goal square.
      • The stone stops there and the game ends in success.
  • You cannot throw the stone more than 10 times in a game. If the stone does not reach the goal in 10 moves, the game ends in failure.

POJ 3009-Curling 2.0(DFS)
Fig. 2: Stone movements

Under the rules, we would like to know whether the stone at the start can reach the goal and, if yes, the minimum number of moves required.

With the initial configuration shown in Fig. 1, 4 moves are required to bring the stone from the start to the goal. The route is shown in Fig. 3(a). Notice when the stone reaches the goal, the board configuration has changed as in Fig. 3(b).

POJ 3009-Curling 2.0(DFS)
Fig. 3: The solution for Fig. D-1 and the final board configuration

Input

The input is a sequence of datasets. The end of the input is indicated by a line containing two zeros separated by a space. The number of datasets never exceeds 100.

Each dataset is formatted as follows.

the width(=w) and the height(=h) of the board 
First row of the board
 
… 
h-th row of the board

The width and the height of the board satisfy: 2 <= w <= 20, 1 <= h <= 20.

Each line consists of w decimal numbers delimited by a space. The number describes the status of the corresponding square.

0 vacant square
1 block
2 start position
3 goal position

The dataset for Fig. D-1 is as follows:

6 6 
1 0 0 2 1 0 
1 1 0 0 0 0 
0 0 0 0 0 3 
0 0 0 0 0 0 
1 0 0 0 0 1 
0 1 1 1 1 1

Output

For each dataset, print a line having a decimal integer indicating the minimum number of moves along a route from the start to the goal. If there are no such routes, print -1 instead. Each line should not have any character other than this number.

Sample Input

2 1
3 2
6 6
1 0 0 2 1 0
1 1 0 0 0 0
0 0 0 0 0 3
0 0 0 0 0 0
1 0 0 0 0 1
0 1 1 1 1 1
6 1
1 1 2 1 1 3
6 1
1 0 2 1 1 3
12 1
2 0 1 1 1 1 1 1 1 1 1 3
13 1
2 0 1 1 1 1 1 1 1 1 1 1 3
0 0

Sample Output

1
4
-1
4
10
-1
写到吐啊有木有。。
题意: 给一张地图。2为起点,3为终点,有一个冰壶,从起点開始滑行。碰到石头(1)停止,这样算1步。越界算失败,问滑到终点最少多少步。到不了终点输出-1;
然后DFS就能够了。

。。悲剧的是地图要初始化。不然会wa到死。

。尽管如今还是不明确地图为什么非要初始化,可能是搜索过程中开全局变量会变异?

#include <algorithm>
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <string>
#include <cctype>
#include <vector>
#include <cstdio>
#include <cmath>
#include <deque>
#include <stack>
#include <map>
#include <set>
#define ll long long
#define maxn 116
#define pp pair<int,int>
#define INF 0x3f3f3f3f
#define max(x,y) ( ((x) > (y)) ?

(x) : (y) )#define min(x,y) ( ((x) > (y)) ?

(y) : (x) )using namespace std;int n, m, ans, sx, sy;int ma[24][24];int dir[4][2] = {{0, 1}, {0, -1}, {1, 0}, { -1, 0}};void dfs(int x, int y, int step){ if (step >= 10) { return ; } if (step >= ans) { return ; } for (int i = 0; i < 4; i++) { int tx = dir[i][0] + x; int ty = dir[i][1] + y; if (tx >= 1 && tx <= m && ty >= 1 && ty <= n && ma[tx][ty] != 1) { while (tx >= 1 && ty >= 1 && tx <= m && ty <= n && ma[tx][ty] != 1 && ma[tx][ty] != 3) { tx += dir[i][0]; ty += dir[i][1]; } if ((tx == 1 || ty == 1 || tx == m || ty == n) && ma[tx][ty] == 0) { continue; } if (ma[tx][ty] == 3) { ans = min(ans, step + 1); return ; } if (ma[tx][ty] == 1) { ma[tx][ty] = 0; dfs(tx - dir[i][0], ty - dir[i][1], step + 1); ma[tx][ty] = 1; } } }}int main(){ while (scanf("%d %d", &n, &m) != EOF) { if (!n && !m) { break; } memset(ma, 0, sizeof(ma)); for (int i = 1; i <= m; i++) for (int j = 1; j <= n; j++) { scanf("%d", &ma[i][j]); if (ma[i][j] == 2) { sx = i; sy = j; } } ans = INF; dfs(sx, sy, 0); if (ans != INF) { printf("%d\n", ans); } else { puts("-1"); } } return 0;}

版权声明:本文博主原创文章,博客,未经同意不得转载。

版权声明:本文内容由互联网用户自发贡献,该文观点仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请联系我们举报,一经查实,本站将立刻删除。

发布者:全栈程序员-站长,转载请注明出处:https://javaforall.net/117032.html原文链接:https://javaforall.net

(0)
全栈程序员-站长的头像全栈程序员-站长


相关推荐

  • teamviwer-无限绑定

    teamviwer-无限绑定

    2021年5月18日
    161
  • SVG可伸缩的矢量图形「建议收藏」

    SVG可伸缩的矢量图形「建议收藏」SVG可伸缩的矢量图形

    2022年4月20日
    46
  • python中encode和decode的区别_python rindex

    python中encode和decode的区别_python rindex1.基本语法1.encode()和decode()都是字符串的函数decode解码encode编码str———>str(Unicode,byte类型)———>str2.decode()与encode()方法可以接受参数,其声明分别为:其中的encoding是指在解码编码过程中使用的编码(此…

    2022年10月6日
    0
  • Sublime Text3 的 Markdown 实时预览全面总结

    Sublime Text3 的 Markdown 实时预览全面总结如前文《SublimeText3的插件管理工具(PackageControl)的安装及使用方法》所说,Sublime有强大的插件扩展功能,本文介绍如何在用Sublime写Markdown文档时,做到效果预览。1.插件介绍先介绍两个有关Markdown的常用插件:MarkdownEditing和MarkdownPreviewMarkdownEditing顾名思义,Ma…

    2022年7月27日
    1
  • IDEA汉化教程(一分钟即可)「建议收藏」

    IDEA汉化教程(一分钟即可)「建议收藏」Idea汉化教程(简单,一分钟即可)步骤打开idea点击左上角的File,然后点击Settings(如下图)进去后点击Plugins,然后点击Marketplace,然后再搜索框搜索chinese然后搜索出东西,点击下面标注的,点击安装然后下载好后再点击右侧的安装(由于我已经安装了,所以才有中文跟显示以安装)。安装完后重启就可以看到idea被汉化了…

    2022年5月11日
    91
  • Spring batch教程 之 spring batch简介

    Spring batch教程 之 spring batch简介SpringBatch介绍在企业领域,有很多应用和系统需要在生产环境中使用批处理来执行大量的业务操作.批处理业务需要自动地对海量数据信息进行各种复杂的业务逻辑处理,同时具备极高的效率,不需要人工干预.执行这种操作通常根据时间事件(如月末统计,通知或信件),或者定期处理那些业务规则超级复杂,数据量非常庞大的业务,(如保险赔款确定,利率调整),也可能是从内部/外部系统抓取到的各种数据,通常需要

    2022年5月11日
    45

发表回复

您的邮箱地址不会被公开。 必填项已用 * 标注

关注全栈程序员社区公众号