大家好，又见面了，我是你们的朋友全栈君。
access：
select top (10) * from table1 where 1=1
db2：
select column from table where 1=1 fetch first 10 rows only
取第三行到第5行的记录
select * from (select row_number() over() as row from table) as temp where row>=3 and row<=5
mysql：
select * from table1 where 1=1 limit 10
sql server:
读取前10条：select top (10) * from table1 where 1=1
读取后10条：select top (10) * from table1 order by id desc
在sqlserver里面，如何读取按照某个排序，第5到10这五个记录
select top 6 * from table where id not in(select top 4 id from table)
oracle：
select * from table1 where rownum<=10
取中间记录：60~100
select * from (select rownum r,a.* from table a where rownum <= 100) where r >= 60;
db2 update多行
update table1 set fild = (select t2.fild from table2 t2 where t2.name =table1 .name);
table2 数据要确保唯一性
db2更改表名
RENAME TABLE table TO table1;
db2表结构一样，数据拷贝
insertinto table select * from table2;
db2取最大值的记录
select * from table1 t1 where t1.name=(select max(date1) from table1 t2 where t2.name=t1.name)
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