// Formats a number with grouped thousands // * example 1: number_format(1234.56); // * returns 1: '1,235' // * example 2: number_format(1234.56, 2, ',', ' '); // * returns 2: '1 234,56' // * example 3: number_format(1234.5678, 2, '.', ''); // * returns 3: '1234.57' // * example 4: number_format(67, 2, ',', '.'); // * returns 4: '67,00' // * example 5: number_format(1000); // * returns 5: '1,000' // * example 6: number_format(67.311, 2); // * returns 6: '67.31' // * example 7: number_format(1000.55, 1); // * returns 7: '1,000.6' // * example 8: number_format(67000, 5, ',', '.'); // * returns 8: '67.000,00000' // * example 9: number_format(0.9, 0); // * returns 9: '1' // * example 10: number_format('1.20', 2); // * returns 10: '1.20' // * example 11: number_format('1.20', 4); // * returns 11: '1.2000' // * example 12: number_format('1.2000', 3); // * returns 12: '1.200' / * number_format * * @param int or float number * @param int decimals * @param string dec_point * @param string thousands_sep * @return string */ function number_format(number, decimals, dec_point, thousands_sep) { var n = !isFinite(+number) ? 0 : +number, prec = !isFinite(+decimals) ? 0 : Math.abs(decimals), sep = (typeof thousands_sep === 'undefined') ? ',' : thousands_sep, dec = (typeof dec_point === 'undefined') ? '.' : dec_point, s = '', toFixedFix = function (n, prec) { var k = Math.pow(10, prec); return '' + Math.round(n * k) / k; }; // Fix for IE parseFloat(0.55).toFixed(0) = 0; s = (prec ? toFixedFix(n, prec) : '' + Math.round(n)).split('.'); if (s[0].length > 3) { s[0] = s[0].replace(//B(?=(?:/d{3})+(?!/d))/g, sep); } if ((s[1] || '').length < prec) { s[1] = s[1] || ''; s[1] += new Array(prec - s[1].length + 1).join('0'); } return s.join(dec); } 版权声明：本文内容由互联网用户自发贡献，该文观点仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请联系我们举报，一经查实，本站将立刻删除。
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