listagg函数替代方案_listagg within group用法

listagg函数替代方案_listagg within group用法这是一个Oracle的列转行函数:LISTAGG()注:oracle11.2才能用 先看示例代码:Sql代码 1.withtempas(  2. select’China’nation,’Guangzhou’cityfromdualunionall 3. select’China’nation,’Shanghai’cityfro

大家好,又见面了,我是你们的朋友全栈君。如果您正在找激活码,请点击查看最新教程,关注关注公众号 “全栈程序员社区” 获取激活教程,可能之前旧版本教程已经失效.最新Idea2022.1教程亲测有效,一键激活。

Jetbrains全系列IDE使用 1年只要46元 售后保障 童叟无欺

这是一个Oracle的列转行函数:LISTAGG()
注:oracle 11.2才能用

 

先看示例代码:

Sql代码 
1.with temp as(  
2.  select ‘China’ nation ,’Guangzhou’ city from dual union all 
3.  select ‘China’ nation ,’Shanghai’ city from dual union all 
4.  select ‘China’ nation ,’Beijing’ city from dual union all 
5.  select ‘USA’ nation ,’New York’ city from dual union all 
6.  select ‘USA’ nation ,’Bostom’ city from dual union all 
7.  select ‘Japan’ nation ,’Tokyo’ city from dual   
8.)  
9.select nation,listagg(city,’,’) within GROUP (order by city)  
10.from temp 
11.group by nation 
with temp as(
  select ‘China’ nation ,’Guangzhou’ city from dual union all
  select ‘China’ nation ,’Shanghai’ city from dual union all
  select ‘China’ nation ,’Beijing’ city from dual union all
  select ‘USA’ nation ,’New York’ city from dual union all
  select ‘USA’ nation ,’Bostom’ city from dual union all
  select ‘Japan’ nation ,’Tokyo’ city from dual
)
select nation,listagg(city,’,’) within GROUP (order by city)
from temp
group by nation 这是最基础的用法:

LISTAGG(XXX,XXX) WITHIN GROUP( ORDER BY XXX)

 

用法就像聚合函数一样,通过Group by语句,把每个Group的一个字段,拼接起来。

非常方便。

 

同样是聚合函数,还有一个高级用法:

就是over(partition by XXX)

也就是说,在你不实用Group by语句时候,也可以使用LISTAGG函数:

Sql代码 
1.with temp as(  
2.  select 500 population, ‘China’ nation ,’Guangzhou’ city from dual union all 
3.  select 1500 population, ‘China’ nation ,’Shanghai’ city from dual union all 
4.  select 500 population, ‘China’ nation ,’Beijing’ city from dual union all 
5.  select 1000 population, ‘USA’ nation ,’New York’ city from dual union all 
6.  select 500 population, ‘USA’ nation ,’Bostom’ city from dual union all 
7.  select 500 population, ‘Japan’ nation ,’Tokyo’ city from dual   
8.)  
9.select population,  
10.       nation,  
11.       city,  
12.       listagg(city,’,’) within GROUP (order by city) over (partition by nation) rank  
13.from temp 
with temp as(
  select 500 population, ‘China’ nation ,’Guangzhou’ city from dual union all
  select 1500 population, ‘China’ nation ,’Shanghai’ city from dual union all
  select 500 population, ‘China’ nation ,’Beijing’ city from dual union all
  select 1000 population, ‘USA’ nation ,’New York’ city from dual union all
  select 500 population, ‘USA’ nation ,’Bostom’ city from dual union all
  select 500 population, ‘Japan’ nation ,’Tokyo’ city from dual
)
select population,
       nation,
       city,
       listagg(city,’,’) within GROUP (order by city) over (partition by nation) rank
from temp

总结:LISTAGG()把它当作SUM()函数来使用就可以了。

 

版权声明:本文内容由互联网用户自发贡献,该文观点仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请联系我们举报,一经查实,本站将立刻删除。

发布者:全栈程序员-站长,转载请注明出处:https://javaforall.net/196361.html原文链接:https://javaforall.net

(0)
全栈程序员-站长的头像全栈程序员-站长


相关推荐

发表回复

您的邮箱地址不会被公开。 必填项已用 * 标注

关注全栈程序员社区公众号