默认C++float转换成int是直接去除小数点后边的数字
- 常规的
float转换为int：
例如：9.34 = (int) 9；9.99 = (int) 9
#include
int main() { float i = 9.34; float j = 9.99; int a, b; a = (int) i; b = (int) j; printf("a = %d\n",a); printf("b = %d\n",b); }
上面的输出结果为：
a = 9 b = 9 -
float转换为int需要四舍五入提高精度，则基本算法如下：
在计算是特别要注意正负数的问题,另外要注意round()函数转换后虽然数值小数点后都变为了零，但此时还是float，还需要转换为int。
#include
int main() { float zer = 0; float i = 9.34; float j = 9.99; float k = -9.34； float m = -9.99； int a, b, c, d, e; int a1, b1, c1, d1, e1; a = (int) (i * 10 + 5) / 10; b = (int) (j * 10 + 5) / 10; c = (int) (k * 10 - 5) / 10; d = (int) (m * 10 - 5) / 10; e = zer; a1 = (int) round(i) b1 = (int) round(j); c1 = (int) round(k); d1 = (int) round(m); e1 = (int) round(zer); printf("a = %d\n",a); printf("b = %d\n",b); printf("c = %d\n",c); printf("d = %d\n",d); printf("e = %d\n",e); printf("round a1 is %f\n", a1); printf("round b1 is %f\n", b1); printf("round c1 is %f\n", c1); printf("round d1 is %f\n", d1); printf("round e1 is %f\n", e1); }
上面的输出结果为：
a = 9 b = 10 c = -9 d = -10 e = 0 round a1 is 9 round b1 is 10 round c1 is -9 round d1 is -10 round e1 is 0 版权声明：本文内容由互联网用户自发贡献，该文观点仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请联系我们举报，一经查实，本站将立刻删除。
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