方法一：GROUP BY分组去重
SELECT T.DOCTOR_ID AS FDOCTORCODE, max(T.DOCTOR_NAME) AS FDOCTORNAME, max(T.DOCTOR_PHONE) AS FDOCTORPHONE, max(T.ORG_ID) AS FORGID, max(T.DEPENT_ID) AS FDEPTCODE FROM CONSULT_SCHEDULE T WHERE ORG_ID = '' AND DEPENT_ID = '1004' GROUP BY DOCTOR_ID 方法二：
SELECT T.DOCTOR_ID AS FDOCTORCODE, T.DOCTOR_NAME AS FDOCTORNAME, T.DOCTOR_PHONE AS FDOCTORPHONE, T.ORG_ID AS FORGID, T.DEPENT_ID AS FDEPTCODE FROM CONSULT_SCHEDULE T, (SELECT MAX(ROWID) ROWID2 FROM CONSULT_SCHEDULE WHERE ORG_ID = '' AND DEPENT_ID = '1004' GROUP BY DOCTOR_ID) T2 WHERE T.ROWID = T2.ROWID2 版权声明：本文内容由互联网用户自发贡献，该文观点仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请联系我们举报，一经查实，本站将立刻删除。
发布者：全栈程序员-站长，转载请注明出处：https://javaforall.net/211528.html原文链接：https://javaforall.net
