gson string转json_string转换成jsonobject

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本文翻译自：Gson: Directly convert String to JsonObject (no POJO)

Can’t seem to figure this out. 似乎无法弄清楚。 I’m attempting JSON tree manipulation in GSON, but I have a case where I do not know or have a POJO to convert a string into, prior to converting to JsonObject . 我正在尝试在GSON中进行JSON树操作，但是在转换为JsonObject之前，我不知道或没有POJO将字符串转换成这种情况。 Is there a way to go directly from a String to JsonObject ? 有没有一种方法可以直接从String转到JsonObject ？

I’ve tried the following (Scala syntax): 我已经尝试了以下（Scala语法）：

val gson = (new GsonBuilder).create

val a: JsonObject = gson.toJsonTree("""{ "a": "A", "b": true }""").getAsJsonObject
val b: JsonObject = gson.fromJson("""{ "a": "A", "b": true }""", classOf[JsonObject])

but a fails, the JSON is escaped and parsed as a JsonString only, and b returns an empty JsonObject . 但是a失败，仅将JSON逸出并解析为JsonString ， b返回一个空的JsonObject 。

Any ideas? 有任何想法吗？

#1楼

参考：https://stackoom.com/question/hfn2/Gson-直接将String转换为JsonObject-无POJO

#2楼

String jsonStr = "{\"a\": \"A\"}";

Gson gson = new Gson();
JsonElement element = gson.fromJson (jsonStr, JsonElement.class);
JsonObject jsonObj = element.getAsJsonObject();

#3楼

Came across a scenario with remote sorting of data store in EXTJS 4.X where the string is sent to the server as a JSON array (of only 1 object). 遇到了一种在EXTJS 4.X中对数据存储进行远程排序的情况，其中该字符串作为JSON数组（只有1个对象）发送到服务器。
Similar approach to what is presented previously for a simple string, just need conversion to JsonArray first prior to JsonObject. 与之前针对简单字符串提供的方法类似，只需要在JsonObject之前先转换为JsonArray。

String from client: [{“property”:”COLUMN_NAME”,”direction”:”ASC”}] 来自客户的字符串： [{“ property”：“ COLUMN_NAME”，“ direction”：“ ASC”}]

String jsonIn = "[{\"property\":\"COLUMN_NAME\",\"direction\":\"ASC\"}]";
JsonArray o = (JsonArray)new JsonParser().parse(jsonIn);

String sortColumn = o.get(0).getAsJsonObject().get("property").getAsString());
String sortDirection = o.get(0).getAsJsonObject().get("direction").getAsString());

#4楼

The simplest way is to use the JsonPrimitive class, which derives from JsonElement , as shown below: 最简单的方法是使用从JsonElement派生的JsonPrimitive类，如下所示：

JsonElement element = new JsonPrimitive(yourString);
JsonObject result = element.getAsJsonObject();

#5楼

I believe this is a more easy approach: 我相信这是一个更简单的方法：

public class HibernateProxyTypeAdapter implements JsonSerializer<HibernateProxy>{

    public JsonElement serialize(HibernateProxy object_,
        Type type_,
        JsonSerializationContext context_) {
        return new GsonBuilder().create().toJsonTree(initializeAndUnproxy(object_)).getAsJsonObject();
        // that will convert enum object to its ordinal value and convert it to json element

    }

    public static <T> T initializeAndUnproxy(T entity) {
        if (entity == null) {
            throw new 
               NullPointerException("Entity passed for initialization is null");
        }

        Hibernate.initialize(entity);
        if (entity instanceof HibernateProxy) {
            entity = (T) ((HibernateProxy) entity).getHibernateLazyInitializer()
                    .getImplementation();
        }
        return entity;
    }
}

And then you will be able to call it like this: 然后您将可以这样调用它：

Gson gson = new GsonBuilder()
        .registerTypeHierarchyAdapter(HibernateProxy.class, new HibernateProxyTypeAdapter())
        .create();

This way all the hibernate objects will be converted automatically. 这样，所有休眠对象将自动转换。

#6楼

//import com.google.gson.JsonObject;  
JsonObject complaint = new JsonObject();
complaint.addProperty("key", "value");