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在翻译加密代码时遇到这个murmurhash2算法了，网上找了几个现成的加密结果对不上，自己手动对照原加密翻译了一般python3版本的。
# -*- coding: utf-8 -*-
# @ Time : 2021/8/26 14:40
# @Note: Please do not use this program for illegal uses.
import ctypes
def unsigned_right_shitf(num, bit):
return ctypes.c_uint32(num).value >> bit
def c_int32(int_num):
return ctypes.c_int32(int_num).value
def murmurhash2(e, timestamp):
array_len = len(e)
f = c_int32(timestamp ^ array_len)
o = 0
while array_len >= 4:
v2 = c_int32(255 & e[o])
o += 1
v3 = c_int32((c_int32(255 & e[o])) << 8)
o += 1
v4 = c_int32((c_int32(255 & e[o])) << 16)
o += 1
v5 = c_int32(c_int32((255 & e[o])) << 24)
n = c_int32(c_int32(c_int32(v2 | v3) | v4) | v5)
v1 = c_int32(65535 & n)
n = 1540483477 * v1 + c_int32((c_int32(1540483477 * (c_int32(n >> 16)) & 65535)) << 16)
n = c_int32(c_int32(n) ^ c_int32(unsigned_right_shitf(n, 24)))
n = 1540483477 * (c_int32(65535 & n)) + c_int32((c_int32(1540483477 * (c_int32(n >> 16)) & 65535)) << 16)
j1 = 1540483477 * (c_int32(65535 & f))
j2 = c_int32((1540483477 * (c_int32(f >> 16)) & 65535) << 16)
f = c_int32((j1 + j2) ^ n)
o += 1
array_len -= 4
f = c_int32(f)
def case1(ff):
ff = c_int32(ff ^ (c_int32(255 & e[o])))
return 1540483477 * (c_int32(65535 & ff)) + c_int32((c_int32(1540483477 * (c_int32(ff >> 16)) & 65535)) << 16)
def case2(ff):
return c_int32(ff ^ c_int32((c_int32(255 & e[o + 1])) << 8))
def case3(ff):
return c_int32(ff ^ c_int32((c_int32(255 & e[o + 2])) << 16))
if array_len == 1:
f = case1(f)
if array_len == 2:
f = case1(case2(f))
if array_len == 3:
f = case1(case2(case3(f)))
f = c_int32(f ^ unsigned_right_shitf(f, 13))
f = 1540483477 * (c_int32(65535 & f)) + c_int32((c_int32(1540483477 * unsigned_right_shitf(f, 16) & 65535)) << 16)
f = c_int32(f ^ unsigned_right_shitf(f, 15))
print("result:", f)
return c_int32(unsigned_right_shitf(f, 0) ^ 1540483477)
if __name__ == '__main__':
murmurhash2(list(b'123abc'), int(time.time()*1000))
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