【Python精华】100个Python练手小程序

100个Python练手小程序，学习python的很好的资料，覆盖了python中的每一部分，可以边学习边练习，更容易掌握python。

for i in range(1,5): for j in range(1,5): for k in range(1,5): if( i != k ) and (i != j) and (j != k): print (i,j,k) 

bonus1 =  * 0.1 bonus2 = bonus1 +  * 0. bonus4 = bonus2 +  * 0.5 bonus6 = bonus4 +  * 0.3 bonus10 = bonus6 +  * 0.15 i = int(raw_input('input gain:\n')) if i <= : bonus = i * 0.1 elif i <= : bonus = bonus1 + (i - ) * 0.075 elif i <= : bonus = bonus2 + (i - ) * 0.05 elif i <= : bonus = bonus4 + (i - ) * 0.03 elif i <= : bonus = bonus6 + (i - ) * 0.015 else: bonus = bonus10 + (i - ) * 0.01 print 'bonus = ',bonus 

include "math.h" main() { long int i,x,y,z; for (i=1;i<;i++) 　{ x=sqrt(i+100); 　　/*x为加上100后开方后的结果*/ 　　y=sqrt(i+268); 　　/*y为再加上168后开方后的结果*/ 　　　if(x*x==i+100&&y*y==i+268)/*如果一个数的平方根的平方等于该数，这说明此数是完全平方数*/ 　　　　printf("\n%ld\n",i); 　} } ''' import math for i in range(10000): #转化为整型值 x = int(math.sqrt(i + 100)) y = int(math.sqrt(i + 268)) if(x * x == i + 100) and (y * y == i + 268): print i 

year = int(raw_input('year:\n')) month = int(raw_input('month:\n')) day = int(raw_input('day:\n')) months = (0,31,59,90,120,151,181,212,243,273,304,334) if 0 <= month <= 12: sum = months[month - 1] else: print 'data error' sum += day leap = 0 if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)): leap = 1 if (leap == 1) and (month > 2): sum += 1 print 'it is the %dth day.' % sum 

l = [] for i in range(3): x = int(raw_input('integer:\n')) l.append(x) l.sort() print l 

print 'Hello Python world!\n' print '*' * 10 for i in range(5): print '* *' print '*' * 10 print '*\n' * 6 

a = 176 b = 219 print chr(b),chr(a),chr(a),chr(a),chr(b) print chr(a),chr(b),chr(a),chr(b),chr(a) print chr(a),chr(a),chr(b),chr(a),chr(a) print chr(a),chr(b),chr(a),chr(b),chr(a) print chr(b),chr(a),chr(a),chr(a),chr(b) 

include "stdio.h" main() { 　int i,j,result; 　printf("\n"); 　for (i=1;i<10;i++) 　　{ for(j=1;j<10;j++) 　　　　{ 　　　　　result=i*j; 　　　　　printf("%d*%d=%-3d",i,j,result);/*-3d表示左对齐，占3位*/ 　　　　} 　　　printf("\n");/*每一行后换行*/ 　　} } for i in range(1,10): for j in range(1,10): result = i * j print '%d * %d = % -3d' % (i,j,result) print '' 

include "stdio.h" main() { int i,j; for(i=0;i<8;i++) 　{ 　　for(j=0;j<8;j++) 　　　if((i+j)%2==0) 　　　　printf("%c%c",219,219); 　　　else 　　　　printf(" "); 　　　printf("\n"); 　} } import sys for i in range(8): for j in range(8): if(i + j) % 2 == 0: sys.stdout.write(chr(219)) sys.stdout.write(chr(219)) else: sys.stdout.write(' ') print '' 

import sys sys.stdout.write(chr(1)) sys.stdout.write(chr(1)) print '' for i in range(1,11): for j in range(1,i): sys.stdout.write(chr(219)) sys.stdout.write(chr(219)) print '' 

main() { long f1,f2; int i; f1=f2=1; for(i=1;i<=20;i++) 　{ printf("%12ld %12ld",f1,f2); 　　　if(i%2==0) printf("\n");/*控制输出，每行四个*/ 　　　f1=f1+f2; /*前两个月加起来赋值给第三个月*/ 　　　f2=f1+f2; /*前两个月加起来赋值给第三个月*/ 　} } f1 = 1 f2 = 1 for i in range(1,21): print '%12d %12d' % (f1,f2) if (i % 2) == 0: print '' f1 = f1 + f2 f2 = f1 + f2 

h = 0 leap = 1 from math import sqrt from sys import stdout for m in range(101,201): k = int(sqrt(m + 1)) for i in range(2,k + 1): if m % i == 0: leap = 0 break if leap == 1: print '%-4d' % m h += 1 if h % 10 == 0: print '' leap = 1 print 'The total is %d' % h 

for n in range(100,1001): i = n / 100 j = n / 10 % 10 k = n % 10 if i * 100 + j * 10 + k == i + j 2 + k 3: print "%-5d" % n 

2.程序源代码：

from sys import stdout n = int(raw_input("input number:\n")) print "n = %d" % n for i in range(2,n + 1): while n != i: if n % i == 0: stdout.write(str(i)) stdout.write("*") n = n / i else: break print "%d" % n 

score = int(raw_input('input score:\n')) if score >= 90: grade = 'A' elif score >= 60: grade = 'B' else: grade = 'C' print '%d belongs to %s' % (score,grade) 

import string s = raw_input('input a string:\n') letters = 0 space = 0 digit = 0 others = 0 for c in s: if c.isalpha(): letters += 1 elif c.isspace(): space += 1 elif c.isdigit(): digit += 1 else: others += 1 print 'char = %d,space = %d,digit = %d,others = %d' % (letters,space,digit,others) 

Tn = 0 Sn = [] n = int(raw_input('n = :\n')) a = int(raw_input('a = :\n')) for count in range(n): Tn = Tn + a a = a * 10 Sn.append(Tn) print Tn Sn = reduce(lambda x,y : x + y,Sn) print Sn 

1. 程序分析：请参照程序<–上页程序14.
   2.程序源代码：
   
   

from sys import stdout for j in range(2,1001): k = [] n = -1 s = j for i in range(1,j): if j % i == 0: n += 1 s -= i k.append(i) if s == 0: print j for i in range(n): stdout.write(k[i]) stdout.write(' ') print k[n] 

Sn = 100.0 Hn = Sn / 2 for n in range(2,11): Sn += 2 * Hn Hn /= 2 print 'Total of road is %f' % Sn print 'The tenth is %f meter' % Hn 

限于篇幅，这里只列出10个，更多Python程序请关注【大数据研习社】公众号回复【Python练手小程序】领取！