大家好，又见面了，我是你们的朋友全栈君。
1.正则表达式的字符串表示 String mobileRegex = “^1(3|4|5|7|8)\\d{9}$”; 字符^意义：表示匹配的字符必须在最前边； 字符$意义：表示待匹配串的结束位置； 字符\d{5,9}意义：\d是数字，{5,9}是5-9位，如果只是验证手机号，且校验的正则表达式如下： /^1[3|5|8][0-9]\d{4,8}$/ ； 不妨写成 /^1[3|5|8]\d{9}$/ ； 2.对手机号字符串的校验 String mobileRegex = “^1(3|4|5|7|8)\\d{9}$”; if (csprop.matches(mobileRegex)){ *******; }else { *******; } 注： String.java /** * Tells whether or not this string matches the given regular expression. * *
An invocation of this method of the form * str.matches(regex) yields exactly the * same result as the expression * *
{@link java.util.regex.Pattern}.{@link * java.util.regex.Pattern#matches(String,CharSequence) * matches}(
regex
,
str
)
* * @param regex * the regular expression to which this string is to be matched * * @return
true if, and only if, this string matches the * given regular expression * * @throws PatternSyntaxException * if the regular expression’s syntax is invalid * * @see java.util.regex.Pattern * * @since 1.4 * @spec JSR-51 */ public boolean matches(String regex) { return Pattern.matches(regex, this); } Pattern.java /** * Compiles the given regular expression and attempts to match the given * input against it. * *
An invocation of this convenience method of the form * *
* Pattern.matches(regex, input);
* * behaves in exactly the same way as the expression * *
* Pattern.compile(regex).matcher(input).matches()
* *
If a pattern is to be used multiple times, compiling it once and reusing * it will be more efficient than invoking this method each time.
* * @param regex * The expression to be compiled * * @param input * The character sequence to be matched * * @throws PatternSyntaxException * If the expression’s syntax is invalid */ public static boolean matches(String regex, CharSequence input) { Pattern p = Pattern.compile(regex); Matcher m = p.matcher(input); return m.matches(); }
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